Erlang software tools...
Generic selectors
Exact matches only
Search in title
Search in content
Post Type Selectors

different LAC for BTSs from the same BSC

Viewing 8 posts - 1 through 8 (of 8 total)
  • Author
    Posts
  • 11th March 2010 at 16:13 #61409
    campus
    Guest

    hi,
    Cells from the same BSC having different LAC could that be a problem??

    11th March 2010 at 21:27 #61410
    Pix
    Guest

    hello,

    no problem, but watch the A interfaces from MSC to BSC, and the BSC processing capacity : the N7 will bring 2x more Paging messages to the BSC.
    1 LAC for 1 BSC : only pagings for that LAC goes through A interface
    2 LACs : twice more pagings must be carried by N7 and processed by BSC.

    12th March 2010 at 07:47 #61411
    Ds
    Guest

    Hi Pix,

    can u tell something more about N7.what is this?

    Thanks in advance

    12th March 2010 at 08:36 #61412
    pix
    Guest

    N7 : there is a “N7” TS on the A interface (BSC – MSC) that carries all the “N7” signalling 🙂
    this signalling is used to carry call setup information (Authentication, Ciphering, Calls Numbers, Handover Messages, etc)

    1 N7 Timeslot can take care of 120 calls.
    The call itself (the TCH if you prefer) is carried by another A nterface timeslot, which is called the “CIC”)

    Cheers
    pix

    12th March 2010 at 13:50 #61413
    campus
    Guest

    pix you are an angel thanks a lot

    15th March 2010 at 04:24 #61414
    Ds
    Guest

    Thanks Pix.

    5th December 2010 at 17:40 #61415
    Taib
    Guest

    Hi Pix,

    I dont think there will be twice number of pagings, as the LAC size will be halved, so the MS present in each LAC will be almost halved assuming the 2 LAC areas are of same size. The bottomline is that the number of paging will be same in the whole BSC as the MS present will remain same.

    5th December 2010 at 17:53 #61416
    pix
    Guest

    taib,

    yes, you are totally right. why did I say something so stupid ?

    Maybe I meant to describe the case where the LACs are shared among several BSC… = the case where the size of the LAC doesn’t depend on the size of the BSC.

    1 LAC is spread over several BSCs -> 1x pagings over n BSC.
    2 LACs = 2x pagings.

    Cheers (and thanks for the correction !!)

  • Author
    Posts
Viewing 8 posts - 1 through 8 (of 8 total)
  • The forum ‘Telecom Design’ is closed to new topics and replies.