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Using a 12.2Kbps codec, is it correct to assume the following?
12.2 Kb/s * 60s = 732 Kb
So an one minute call is the same as 732 Kb of data
I have the felling something is wrong, Could someone help me with this.
Thanks!
Hello jlnh,
It is fine, don’t worry. A call does indeed need a constant 12.2kb/s (useful) throughput. The actual throughput on the air of a TS is above 22kbps, but that’s including all the “radio” protection around the useful signal. You shouldn’t be counting it.
Just don’t forget that the timeslot has also a useful throughput capacity of 12.2kb/s and you have no reason to worry. I’m interested to know what you would do with such a figure ?
If you want to compute the throughput the voice is going to use in an IP transmission network, then you should also add the headers and the related signalling (about +0.9kb/s per call).
Regards,
Pix
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