Badu,
Yes, I think i’ve heard about it :))
Sorry about this, actually i think i made the assumption that one operator gets only 1 NCC. Therefore, only 8 BSIC available. (1 NCC / 0…7 BCC)
This assumption is wrong, because one operator can actually have more than 1 NCC.
Thanks for pointing the error out 😉
Pix