4th September 2003 at 07:43
#35141
Nguyen
Guest
Very simple.
The total timeslots is 4×8=32. The number of SDCCH is 16 => occupied 16/8=2 timeslots. 16 SDCCH => non-combined configuration => need 1 timeslot for 1BCCH+9CCCH.
Hence the available timeslots for TCH is: 32-2-1=29.
ok?